(x^2+5)+(5x+1)=

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Solution for (x^2+5)+(5x+1)= equation:


Simplifying
(x2 + 5) + (5x + 1) = 0

Reorder the terms:
(5 + x2) + (5x + 1) = 0

Remove parenthesis around (5 + x2)
5 + x2 + (5x + 1) = 0

Reorder the terms:
5 + x2 + (1 + 5x) = 0

Remove parenthesis around (1 + 5x)
5 + x2 + 1 + 5x = 0

Reorder the terms:
5 + 1 + 5x + x2 = 0

Combine like terms: 5 + 1 = 6
6 + 5x + x2 = 0

Solving
6 + 5x + x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(3 + x)(2 + x) = 0

Subproblem 1

Set the factor '(3 + x)' equal to zero and attempt to solve: Simplifying 3 + x = 0 Solving 3 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + x = 0 + -3 Combine like terms: 3 + -3 = 0 0 + x = 0 + -3 x = 0 + -3 Combine like terms: 0 + -3 = -3 x = -3 Simplifying x = -3

Subproblem 2

Set the factor '(2 + x)' equal to zero and attempt to solve: Simplifying 2 + x = 0 Solving 2 + x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + x = 0 + -2 x = 0 + -2 Combine like terms: 0 + -2 = -2 x = -2 Simplifying x = -2

Solution

x = {-3, -2}

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